fix

img/shear.svg

@@ -24,8 +24,8 @@
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@@ -164,5 +131,27 @@
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 </svg>

notes.tex

@@ -2673,7 +2673,10 @@ At $t = 0$, $X(A, t= 0) = A \implies F = \mathbb I \implies J = 1$
 
 Since $J(t = 0) = 1$, $J \ne 0$ always implies $J(t) > 0$ 
 
-\begin{ex} Uniform diletion
+\week{}
+\lecture
+
+\begin{ex} Uniform dilation
 
         Motion according to $A \mapsto X(A,t) = \alpha(t) A$ where
             $\alpha(t) \ge 0, \alpha(0) = 1$.